| Series-parallel R, L, and CNow that we've seen how series and parallel 
                    AC circuit analysis is not fundamentally different than DC 
                    circuit analysis, it should come as no surprise that 
                    series-parallel analysis would be the same as well, just 
                    using complex numbers instead of scalar to represent 
                    voltage, current, and impedance.  Take this series-parallel circuit for 
                    example:  
                      The first order of business, as usual, is to 
                    determine values of impedance (Z) for all components based 
                    on the frequency of the AC power source. To do this, we need 
                    to first determine values of reactance (X) for all inductors 
                    and capacitors, then convert reactance (X) and resistance 
                    (R) figures into proper impedance (Z) form:  
                        
                      Now we can set up the initial values in our 
                    table:  
                      Being a series-parallel combination 
                    circuit, we must reduce it to a total impedance in more than 
                    one step. The first step is to combine L and C2 
                    as a series combination of impedances, by adding their 
                    impedances together. Then, that impedance will be combined 
                    in parallel with the impedance of the resistor, to arrive at 
                    another combination of impedances. Finally, that quantity 
                    will be added to the impedance of C1 to arrive at 
                    the total impedance.  In order that our table may follow all these 
                    steps, it will be necessary to add additional columns to it 
                    so that each step may be represented. Adding more columns 
                    horizontally to the table shown above would be impractical 
                    for formatting reasons, so I will place a new row of columns 
                    underneath, each column designated by its respective 
                    component combination:  
                      Calculating these new (combination) 
                    impedances will require complex addition for series 
                    combinations, and the "reciprocal" formula for complex 
                    impedances in parallel. This time, there is no avoidance of 
                    the reciprocal formula: the required figures can be arrived 
                    at no other way!  
                      Seeing as how our second table contains a 
                    column for "Total," we can safely discard that column from 
                    the first table. This gives us one table with four columns 
                    and another table with three columns.  Now that we know the total impedance (818.34 
                    Ω ∠ -58.371o) and the total voltage (120 volts ∠ 
                    0o), we can apply Ohm's Law (I=E/Z) vertically in 
                    the "Total" column to arrive at a figure for total current:
                     
                      At this point we ask ourselves the question: 
                    are there any components or component combinations which 
                    share either the total voltage or the total current? In this 
                    case, both C1 and the parallel combination 
                    R//(L--C2) share the same (total) current, since 
                    the total impedance is composed of the two sets of 
                    impedances in series. Thus, we can transfer the figure for 
                    total current into both columns:  
                        
 
 
                      Now, we can calculate voltage drops across C1 
                    and the series-parallel combination of R//(L--C2) 
                    using Ohm's Law (E=IZ) vertically in those table columns:
                     
                        
                      A quick double-check of our work at this 
                    point would be to see whether or not the voltage drops 
                    across C1 and the series-parallel combination of 
                    R//(L--C2) indeed add up to the total. According 
                    to Kirchhoff's Voltage Law, they should!  
                      That last step was merely a precaution. In a 
                    problem with as many steps as this one has, there is much 
                    opportunity for error. Occasional cross-checks like that one 
                    can save a person a lot of work and unnecessary frustration 
                    by identifying problems prior to the final step of the 
                    problem.  After having solved for voltage drops across 
                    C1 and the combination R//(L--C2), we 
                    again ask ourselves the question: what other components 
                    share the same voltage or current? In this case, the 
                    resistor (R) and the combination of the inductor and the 
                    second capacitor (L--C2) share the same voltage, 
                    because those sets of impedances are in parallel with each 
                    other. Therefore, we can transfer the voltage figure just 
                    solved for into the columns for R and L--C2:  
                        
 
 
                      Now we're all set for calculating current 
                    through the resistor and through the series combination L--C2. 
                    All we need to do is apply Ohm's Law (I=E/Z) vertically in 
                    both of those columns:  
                        
 
 
                      Another quick double-check of our work at 
                    this point would be to see if the current figures for L--C2 
                    and R add up to the total current. According to Kirchhoff's 
                    Current Law, they should:  
                      Since the L and C2 are connected 
                    in series, and since we know the current through their 
                    series combination impedance, we can distribute that current 
                    figure to the L and C2 columns following the rule 
                    of series circuits whereby series components share the same 
                    current:  
                      With one last step (actually, two 
                    calculations), we can complete our analysis table for this 
                    circuit. With impedance and current figures in place for L 
                    and C2, all we have to do is apply Ohm's Law (E=IZ) 
                    vertically in those two columns to calculate voltage drops.
                     
                      Now, let's turn to SPICE for a computer 
                    verification of our work:  
                      
 
 ac series-parallel r-l-c circuit  
v1 1 0 ac 120 sin       
vit 1 2 ac 0    
vilc 3 4 ac 0   
vir 3 6 ac 0    
c1 2 3 4.7u     
l 4 5 650m      
c2 5 0 1.5u     
r 6 0 470       
.ac lin 1 60 60 
.print ac v(2,3) vp(2,3) i(vit) ip(vit) 
.print ac v(4,5) vp(4,5) i(vilc) ip(vilc)       
.print ac v(5,0) vp(5,0) i(vilc) ip(vilc)       
.print ac v(6,0) vp(6,0) i(vir) ip(vir) 
.end   freq          v(2,3)      vp(2,3)     i(vit)      ip(vit)     C1  
6.000E+01     8.276E+01  -3.163E+01   1.466E-01   5.837E+01 freq          v(4,5)      vp(4,5)     i(vilc)     ip(vilc)    L
6.000E+01     1.059E+01  -1.388E+02   4.323E-02   1.312E+02 freq          v(5)        vp(5)       i(vilc)     ip(vilc)    C2
6.000E+01     7.645E+01   4.122E+01   4.323E-02   1.312E+02
 freq          v(6)        vp(6)       i(vir)      ip(vir)     R
6.000E+01     6.586E+01   4.122E+01   1.401E-01   4.122E+01
 Each line of the SPICE output listing gives 
                    the voltage, voltage phase angle, current, and current phase 
                    angle for C1, L, C2, and R, in that 
                    order. As you can see, these figures do concur with our 
                    hand-calculated figures in the circuit analysis table.  As daunting a task as series-parallel AC 
                    circuit analysis may appear, it must be emphasized that 
                    there is nothing really new going on here besides the use of 
                    complex numbers. Ohm's Law (in its new form of E=IZ) still 
                    holds true, as do the voltage and current Laws of Kirchhoff. 
                    While there is more potential for human error in carrying 
                    out the necessary complex number calculations, the basic 
                    principles and techniques of series-parallel circuit 
                    reduction are exactly the same.  
                      
                      REVIEW: 
                      Analysis of series-parallel AC circuits is 
                      much the same as series-parallel DC circuits. The only 
                      substantive difference is that all figures and 
                      calculations are in complex (not scalar) form. 
                      It is important to remember that before 
                      series-parallel reduction (simplification) can begin, you 
                      must determine the impedance (Z) of every resistor, 
                      inductor, and capacitor. That way, all component values 
                      will be expressed in common terms (Z) instead of an 
                      incompatible mix of resistance (R), inductance (L), and 
                      capacitance (C).  |