| Series R, L, and CLet's take the following example circuit and 
                    analyze it:  
                      The first step is to determine the 
                    reactances (in ohms) for the inductor and the capacitor.  
                      The next step is to express all resistances 
                    and reactances in a mathematically common form: impedance. 
                    Remember that an inductive reactance translates into a 
                    positive imaginary impedance (or an impedance at +90o), 
                    while a capacitive reactance translates into a negative 
                    imaginary impedance (impedance at -90o). 
                    Resistance, of course, is still regarded as a purely "real" 
                    impedance (polar angle of 0o):  
                        
 
 
                      Now, with all quantities of opposition to 
                    electric current expressed in a common, complex number 
                    format (as impedances, and not as resistances or reactances), 
                    they can be handled in the same way as plain resistances in 
                    a DC circuit. This is an ideal time to draw up an analysis 
                    table for this circuit and insert all the "given" figures 
                    (total voltage, and the impedances of the resistor, 
                    inductor, and capacitor).  
                      Unless otherwise specified, the source 
                    voltage will be our reference for phase shift, and so will 
                    be written at an angle of 0o. Remember that there 
                    is no such thing as an "absolute" angle of phase shift for a 
                    voltage or current, since it's always a quantity relative to 
                    another waveform. Phase angles for impedance, however (like 
                    those of the resistor, inductor, and capacitor), are known 
                    absolutely, because the phase relationships between voltage 
                    and current at each component are absolutely defined.  Notice that I'm assuming a perfectly 
                    reactive inductor and capacitor, with impedance phase angles 
                    of exactly +90 and -90o, respectively. Although 
                    real components won't be perfect in this regard, they should 
                    be fairly close. For simplicity, I'll assume perfectly 
                    reactive inductors and capacitors from now on in my example 
                    calculations except where noted otherwise.  Since the above example circuit is a series 
                    circuit, we know that the total circuit impedance is equal 
                    to the sum of the individuals, so:  
                      Inserting this figure for total impedance 
                    into our table:  
                      We can now apply Ohm's Law (I=E/R) 
                    vertically in the "Total" column to find total current for 
                    this series circuit:  
                      Being a series circuit, current must be 
                    equal through all components. Thus, we can take the figure 
                    obtained for total current and distribute it to each of the 
                    other columns:  
                      Now we're prepared to apply Ohm's Law (E=IZ) 
                    to each of the individual component columns in the table, to 
                    determine voltage drops:  
                      Notice something strange here: although our 
                    supply voltage is only 120 volts, the voltage across the 
                    capacitor is 137.46 volts! How can this be? The answer lies 
                    in the interaction between the inductive and capacitive 
                    reactances. Expressed as impedances, we can see that the 
                    inductor opposes current in a manner precisely opposite that 
                    of the capacitor. Expressed in rectangular form, the 
                    inductor's impedance has a positive imaginary term and the 
                    capacitor has a negative imaginary term. When these two 
                    contrary impedances are added (in series), they tend to 
                    cancel each other out! Although they're still added 
                    together to produce a sum, that sum is actually less 
                    than either of the individual (capacitive or inductive) 
                    impedances alone. It is analogous to adding together a 
                    positive and a negative (scalar) number: the sum is a 
                    quantity less than either one's individual absolute value.
                     If the total impedance in a series circuit 
                    with both inductive and capacitive elements is less than the 
                    impedance of either element separately, then the total 
                    current in that circuit must be greater than what it 
                    would be with only the inductive or only the capacitive 
                    elements there. With this abnormally high current through 
                    each of the components, voltages greater than the source 
                    voltage may be obtained across some of the individual 
                    components! Further consequences of inductors' and 
                    capacitors' opposite reactances in the same circuit will be 
                    explored in the next chapter.  Once you've mastered the technique of 
                    reducing all component values to impedances (Z), analyzing 
                    any AC circuit is only about as difficult as analyzing any 
                    DC circuit, except that the quantities dealt with are vector 
                    instead of scalar. With the exception of equations dealing 
                    with power (P), equations in AC circuits are the same as 
                    those in DC circuits, using impedances (Z) instead of 
                    resistances (R). Ohm's Law (E=IZ) still holds true, and so 
                    do Kirchhoff's Voltage and Current Laws.  To demonstrate Kirchhoff's Voltage Law in an 
                    AC circuit, we can look at the answers we derived for 
                    component voltage drops in the last circuit. KVL tells us 
                    that the algebraic sum of the voltage drops across the 
                    resistor, inductor, and capacitor should equal the applied 
                    voltage from the source. Even though this may not look like 
                    it is true at first sight, a bit of complex number addition 
                    proves otherwise:  
                      Aside from a bit of rounding error, the sum 
                    of these voltage drops does equal 120 volts. Performed on a 
                    calculator (preserving all digits), the answer you will 
                    receive should be exactly 120 + j0 volts.  We can also use SPICE to verify our figures 
                    for this circuit:  
                        ac r-l-c circuit   
v1 1 0 ac 120 sin       
r1 1 2 250      
l1 2 3 650m     
c1 3 0 1.5u     
.ac lin 1 60 60 
.print ac v(1,2) v(2,3) v(3,0) i(v1)    
.print ac vp(1,2) vp(2,3) vp(3,0) ip(v1) 
.end       freq          v(1,2)      v(2,3)      v(3)        i(v1)       
6.000E+01     1.943E+01   1.905E+01   1.375E+02   7.773E-02
freq          vp(1,2)     vp(2,3)     vp(3)       ip(v1)      
6.000E+01     8.068E+01   1.707E+02  -9.320E+00  -9.932E+01   
                      The SPICE simulation shows our 
                    hand-calculated results to be accurate.  As you can see, there is little difference 
                    between AC circuit analysis and DC circuit analysis, except 
                    that all quantities of voltage, current, and resistance 
                    (actually, impedance) must be handled in complex 
                    rather than scalar form so as to account for phase angle. 
                    This is good, since it means all you've learned about DC 
                    electric circuits applies to what you're learning here. The 
                    only exception to this consistency is the calculation of 
                    power, which is so unique that it deserves a chapter devoted 
                    to that subject alone.  
                      
                      REVIEW: 
                      Impedances of any kind add in series: ZTotal 
                      = Z1 + Z2 + . . . Zn 
                      Although impedances add in series, the 
                      total impedance for a circuit containing both inductance 
                      and capacitance may be less than one or more of the 
                      individual impedances, because series inductive and 
                      capacitive impedances tend to cancel each other out. This 
                      may lead to voltage drops across components exceeding the 
                      supply voltage! 
                      All rules and laws of DC circuits apply to 
                      AC circuits, so long as values are expressed in complex 
                      form rather than scalar. The only exception to this 
                      principle is the calculation of power, which is 
                      very different for AC.  |