| Calculating electric 
                    powerWe've seen the formula for determining the 
                    power in an electric circuit: by multiplying the voltage in 
                    "volts" by the current in "amps" we arrive at an answer in 
                    "watts." Let's apply this to a circuit example:  
                      In the above circuit, we know we have a 
                    battery voltage of 18 volts and a lamp resistance of 3 Ω. 
                    Using Ohm's Law to determine current, we get:  
                      Now that we know the current, we can take 
                    that value and multiply it by the voltage to determine 
                    power:  
                      Answer: the lamp is dissipating (releasing) 
                    108 watts of power, most likely in the form of both light 
                    and heat.  Let's try taking that same circuit and 
                    increasing the battery voltage to see what happens. 
                    Intuition should tell us that the circuit current will 
                    increase as the voltage increases and the lamp resistance 
                    stays the same. Likewise, the power will increase as well:
                     
                      Now, the battery voltage is 36 volts instead 
                    of 18 volts. The lamp is still providing 3 Ω of electrical 
                    resistance to the flow of electrons. The current is now:  
                      This stands to reason: if I = E/R, and we 
                    double E while R stays the same, the current should double. 
                    Indeed, it has: we now have 12 amps of current instead of 6. 
                    Now, what about power?  
                      Notice that the power has increased just as 
                    we might have suspected, but it increased quite a bit more 
                    than the current. Why is this? Because power is a function 
                    of voltage multiplied by current, and both voltage 
                    and current doubled from their previous values, the power 
                    will increase by a factor of 2 x 2, or 4. You can check this 
                    by dividing 432 watts by 108 watts and seeing that the ratio 
                    between them is indeed 4.  Using algebra again to manipulate the 
                    formulae, we can take our original power formula and modify 
                    it for applications where we don't know both voltage and 
                    resistance:  If we only know voltage (E) and resistance 
                    (R):  
                      If we only know current (I) and resistance 
                    (R):  
                      An historical note: it was James Prescott 
                    Joule, not Georg Simon Ohm, who first discovered the 
                    mathematical relationship between power dissipation and 
                    current through a resistance. This discovery, published in 
                    1841, followed the form of the last equation (P = I2R), 
                    and is properly known as Joule's Law. However, these power 
                    equations are so commonly associated with the Ohm's Law 
                    equations relating voltage, current, and resistance (E=IR ; 
                    I=E/R ; and R=E/I) that they are frequently credited to Ohm.
                     
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